A. 20 B. 23
C. 27 D. 150
ANSWER & EXPLANATION
ANSWER:B
Explanation
Discuss the solution
Given product 2 numbers and sum of their squares,
apply, (a + b)2 = (a2 + b2 + 2ab)
(a + b)2 = 289 + 2 * 120 = 529 => a+b = 23.
Explanation
Discuss the solution
Given product 2 numbers and sum of their squares,
apply, (a + b)2 = (a2 + b2 + 2ab)
(a + b)2 = 289 + 2 * 120 = 529 => a+b = 23.
A.82 B. 81
C. 83 D. 80
ANSWER & EXPLANATION
ANSWER:B
Solution:
For x=4, Remainder 3x81=0
And, Remainder 3x162=81
Solution:
For x=4, Remainder 3x81=0
And, Remainder 3x162=81
A. 0. B.1
C. 4 D. 7
ANSWER & EXPLANATION
ANSWER: A
Since the exponents are even, we can apply the property that,
If 'x' is even ax–bx is always divisible by (a+b).
6256-4256 will always be divisible by (6+4)=10.
Now any number multiplied by 10 gives the last digit as 'zero'.
Alternative:
The last digit of both the number are same as '6'
Thus after subtracting the unit's digit be '0'.
Since the exponents are even, we can apply the property that,
If 'x' is even ax–bx is always divisible by (a+b).
6256-4256 will always be divisible by (6+4)=10.
Now any number multiplied by 10 gives the last digit as 'zero'.
Alternative:
The last digit of both the number are same as '6'
Thus after subtracting the unit's digit be '0'.
A. 1 B.3
C. 0 D.7
ANSWER & EXPLANATION
ANSWER: C
12314 is not divisible by 4
12334 is not divisible by 4
12304 is divisible by 4.
12314 is not divisible by 4
12334 is not divisible by 4
12304 is divisible by 4.
A. 1349 B.6286
C.2686 D. 1341
ANSWER & EXPLANATION
ANSWER: A
First digit is 1/3 second digit => The numbers can be 1 & 3, 2& 6, 3 & 9.
First + second = third => we can eliminate 3 & 9 since 3 + 9 = 12.
Last is 3 times the second =>
we can eliminate option 2 & 6 since 3 * 6 = 18.
Hence the number is 1349.
First digit is 1/3 second digit => The numbers can be 1 & 3, 2& 6, 3 & 9.
First + second = third => we can eliminate 3 & 9 since 3 + 9 = 12.
Last is 3 times the second =>
we can eliminate option 2 & 6 since 3 * 6 = 18.
Hence the number is 1349.
A. 13 B.12
C. 14 D. 11
ANSWER & EXPLANATION
ANSWER: B
12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45,48.
13 Numbers.
10/3 = 3 and 50/3 = 16 ==> 16 - 3 = 13. Therefore 13 digits.
12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45,48.
13 Numbers.
10/3 = 3 and 50/3 = 16 ==> 16 - 3 = 13. Therefore 13 digits.
A. 69
B. 78
C. 96
D.Cannot be determined
ANSWER & EXPLANATION
ANSWER :D
Explanation:
Let the ten's digit be x and unit's digit be y.
Then, x + y = 15 and x - y = 3 or y - x = 3.
Solving x + y = 15 and x - y = 3, we get: x = 9, y = 6.
Solving x + y = 15 and y - x = 3, we get: x = 6, y = 9.
So, the number is either 96 or 69.
Hence, the number cannot be determined.
Explanation:
Let the ten's digit be x and unit's digit be y.
Then, x + y = 15 and x - y = 3 or y - x = 3.
Solving x + y = 15 and x - y = 3, we get: x = 9, y = 6.
Solving x + y = 15 and y - x = 3, we get: x = 6, y = 9.
So, the number is either 96 or 69.
Hence, the number cannot be determined.
A. 34 B. 38
C. 42 D. 46
ANSWER & EXPLANATION
ANSWER: C
Explanation:
Let the numbers be x and x + 2
Then, (x + 2)2 - x2 = 84
4x + 4 = 84
4x = 80
x = 20
The required sum = x + (x + 2) = 2x + 2 = 42
Explanation:
Let the numbers be x and x + 2
Then, (x + 2)2 - x2 = 84
4x + 4 = 84
4x = 80
x = 20
The required sum = x + (x + 2) = 2x + 2 = 42
A. 99840 B. 99900
C. 99960 D. 99990
ANSWER & EXPLANATION
ANSWER: C
The number should be divisible by 10 (2, 5), 15 (3, 5), 21 (3, 7), and 28 (4, 7).
Hence, it is enough to check whether the number is divisibile by 3, 4, 5 and 7.
Test of divisibility by 3: Sum of the digits will be divisible by 3 if a number is divisible by 3.
Test of divisibility by 4: The righmost two digits viz., the units and tens digits will be divisible by 4 if a number is divisible by 4. For e.g, 1232 is divisible by 4 because 32 is divisible by 4.
Test of divisibility by 5: The units digit is either 5 or 0.
99960 is the only number which is divisible by 3, 4, 5 and 7.
Correct answer choice (3)
The number should be divisible by 10 (2, 5), 15 (3, 5), 21 (3, 7), and 28 (4, 7).
Hence, it is enough to check whether the number is divisibile by 3, 4, 5 and 7.
Test of divisibility by 3: Sum of the digits will be divisible by 3 if a number is divisible by 3.
Test of divisibility by 4: The righmost two digits viz., the units and tens digits will be divisible by 4 if a number is divisible by 4. For e.g, 1232 is divisible by 4 because 32 is divisible by 4.
Test of divisibility by 5: The units digit is either 5 or 0.
99960 is the only number which is divisible by 3, 4, 5 and 7.
Correct answer choice (3)
A.4 B.6
C. 8 D. 5
ANSWER & EXPLANATION
ANSWER: A
DETAILED SOLUTION
1080 = 23 * 33 * 5. For any perfect square, all the powers of the primes
have to be even numbers. So, if the factor is of the form 2a * 3b * 5c.
The values 'a' can take are 0 and 2, b can take are 0 and 2, and c can take the value 0.
Totally there are 4 possibilities. 1, 4, 9, and 36.
Correct Answer: 4 Possibilities.
DETAILED SOLUTION
1080 = 23 * 33 * 5. For any perfect square, all the powers of the primes
have to be even numbers. So, if the factor is of the form 2a * 3b * 5c.
The values 'a' can take are 0 and 2, b can take are 0 and 2, and c can take the value 0.
Totally there are 4 possibilities. 1, 4, 9, and 36.
Correct Answer: 4 Possibilities.
A. 2, 4 and 8 B. 2 and 4
C. 2 D. 100
ANSWER & EXPLANATION
ANSWER: C
The sum of the first 100 natural numbers is 101
is an odd number and 50 is divisible by 2
Hence, 50*101 will be divisible by 2
The sum of the first 100 natural numbers is 101
is an odd number and 50 is divisible by 2
Hence, 50*101 will be divisible by 2