FORMULAE
1.
Concept of Percentage : By a certain percent ,we
mean that many hundredths. Thus x percent means x hundredths, written as x%.
To express x% as a fraction : We have , x% = x/100.
Thus, 20% =20/100 =1/5; 48% =48/100
=12/25, etc.
To express a/b as a percent : We have, a/b =((a/b)*100)%.
Thus, ¼
=[(1/4)*100] = 25%; 0.6 =6/10 =3/5 =[(3/5)*100]% =60%
2.
If the price of a commodity increases by R%, then the
reduction in consumption so asnot to increase the expenditure is
[R/(100+R))*100]%.
If the
price of the commodity decreases by R%,then the increase in consumption so as
to decrease the expenditure is
[(R/(100-R)*100]%.
3. Results on Population : Let the
population of the town be P now and suppose it increases at the rate of
R% per annum, then :
1. Population
after nyeras = P [1+(R/100)]^n.
2. Population
n years ago = P /[1+(R/100)]^n.
4. Results on Depreciation : Let the present value of a machine be P.
Suppose it depreciates at the rate
R% per annum. Then,
1. Value of
the machine after n years = P[1-(R/100)]n.
2. Value of
the machine n years ago = P/[1-(R/100)]n.
5.
If A is R% more than B, then B is less than A by
[(R/(100+R))*100]%.
If
A is R% less than B , then B is more than A by
[(R/(100-R))*100]%.